Basic knowledge.

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pre65
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#1 Basic knowledge.

Post by pre65 »

I do know a bit about the theory of valve circuits, but there are gaps in my knowledge that confuse me. So I'd like to seek help. Some of these questions may seem too basic for one who has built so many amps, but that's me, the one and only me. :wink:

1) When one is seeking data to bias the grid of a driving valve, is the bias needed the same as the likely max input signal ? ie if the max input volts is 2v (CD output voltage) does one bias the grid at -2v ?

2) If so, what would be a good input voltage for a healthy input signal from a pre amp, mainly fed from a DAC.

If this knowledge is available from an external source that's easy to read a link would be appreciated. If it's in MJ third edition, what section ?
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Nick
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#2

Post by Nick »

Ok, first part IMHO is you need to go back to the loads lines and see why you need what headroom you need for a given input,

second part, remember 2v from a CD player is 2v RMS, so the peak voltage is 2 * 1.414 or 2,828

third part, try and keep away from the zero volt grid line (see part one), so in this case I would suggest -3v bias at least for the input directly from a CD.
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pre65
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#3

Post by pre65 »

Thanks Nick.

More by luck than judgement the 12HG7 I've just installed in the PSE pentode amp are biased at -2.8v, sounds near enough.

I'll try and find that DTB tutorial on load lines, it's on the forum somewhere.
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#4

Post by Mike H »

Yep.

Ergo you couldn't run such a CD player directly into an ECC83, for example, 'cause its DC bias Volts is am very tiny :D

It would clip like a clipping clippy thing.....
 
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#5

Post by Mike H »

Appendix ~ depends on the source impedance, feasibly possible it might be driven into A2
 
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#6

Post by pre65 »

Question 3. This came up when talking to a friend the other week.

When using an anode choke (like I do on 112a pre) is there any reason to have a CCS between the PSU and the choke.

We both thought there was a reason that would prohibit such a configuration, but could not find what it was.
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#7

Post by Nick »

No. There is no reason why you would, and one big reason why you shouldn't

To work out what the reason is, read up about inductors. (hint: what happens if the current through a inductor is constant)
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#8

Post by pre65 »

Ah, so in effect, with constant current the choke ceases to function as a choke.:)
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#9

Post by Dave the bass »

pre65 wrote: I'll try and find that DTB tutorial on load lines, it's on the forum somewhere.
This one Phil?

http://www.audio-talk.co.uk/phpBB2/view ... =loadlines

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#10

Post by pre65 »

Dave the bass wrote:
pre65 wrote: I'll try and find that DTB tutorial on load lines, it's on the forum somewhere.
This one Phil?

http://www.audio-talk.co.uk/phpBB2/view ... =loadlines

DTB
Cheers Dave, I've saved it in my "hi-fi" favourites section so I can have a good read. :)
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#11

Post by Nick »

Ah, so in effect, with constant current the choke ceases to function as a choke
The choke will always be a choke, and so will always function as a choke.
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#12

Post by Mike H »

<imagination mode>
If choke is supplied via a CCS, it's current can't change, so it can't make any AC signal Volts across itself. Or not a lot :?:
Would be mostly like a CCS with a resistor in series, and the CCS is doing most of the work. :?: :?:
</imagination mode>
 
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#13

Post by IslandPink »

V = L*dI/dt is what Mike said .

Nick wrote: The choke will always be a choke, and so will always function as a choke.
But if a choke fails to act like a choke, in the woods, and nobody sees it fail to act like a choke, did it .... no sorry you are correct, Nick :D
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#14

Post by Nick »

Yep, I was sort of hoping Phil would take the hint and go and try and read about just what a inductor is.

Resistor: current is proportional to voltage

I = E / R

Capacitor: current is proportional to the rate of change of voltage

I = C dv/dt

Inductor: voltage is proportional to the rate of change of current

V = L di/dt
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#15

Post by pre65 »

[quote="Nick"]Yep, I was sort of hoping Phil would take the hint and go and try and read about just what a inductor is.

I did, but I did not explain it very well. :oops:
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